
Tuesday, October 27, 2015
coakroach

Hardy-Weinberg.
My Q2 was .32 and the population was 1000, so to get the number of recessive trait you have to multiply .32*1000
Which gave me 320 as my recessive trait
The recessive phenotype is already given to us which is .32
To the the number of individual recessive allele(q) i √(.32) which gave me .57
To get the number of the dominant allele(p) i subtracted 1-.q which is 1-.57 which gave me .43
To get the number of dominat phenotype you square root your dominat allele(p) √(.43)= .66
Lastly for the heterozygoats individuals (2pq) you multiply 2(.43)(.57)= .49
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